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Boltzmann's equation

We're interested in finding an equation that describes the distribution of stars in a galaxy. So we want to know is how many stars there are in a small volume $ d\hbox{$\bf x$}$ around a position $ \hbox{$\bf x$}$, that have velocity in a small interval $ d\dot\hbox{$\bf x$}$ around a given velocity $ \dot\hbox{$\bf x$}$. This density of stars, $ f(\hbox{$\bf x$},\dot\hbox{$\bf x$},t)$, is called the distribution function. If we don't care about the velocity of stars, then we can integrate $ f$ over all velocities, to obtain the density of stars,

$\displaystyle n(\hbox{$\bf x$},t)=\int f(\hbox{$\bf x$},\dot\hbox{$\bf x$},t)\,d\dot\hbox{$\bf x$}\,.$ (8.15)

Now we only have to realise that stars acts as our cars on the motor way, and hence $ f$ should satisfy the continuity equation (8.14). The way to do it is to substitute for the $ l$ coordinates in that equation the positions and velocities of the stars,


$\displaystyle \hbox{$\bf l$}$ $\displaystyle \equiv$ $\displaystyle (\hbox{$\bf x$},\hbox{$\bf v$})$  
$\displaystyle \dot\hbox{$\bf l$}$ $\displaystyle \equiv$ $\displaystyle (\hbox{$\bf v$},\dot\hbox{$\bf v$}) = (\hbox{$\bf v$},-\nabla\Phi)\,,$ (8.16)

where I've written $ -\nabla\Phi$ for the gravitational acceleration $ \dot\hbox{$\bf v$}$ of the star.

So this $ \hbox{$\bf l$}$ vector has 6 coordinates, $ l_\alpha=\hbox{$\bf x$}$ for $ \alpha=1\rightarrow 3$, and $ l_\alpha=\hbox{$\bf v$}$ for $ \alpha=4\rightarrow
6$. Now these coordinates are very special, since


$\displaystyle \sum_{\alpha=1}^6 {\partial\dot l_\alpha\over \partial l_\alpha}$ $\displaystyle =$ $\displaystyle \sum_{i=1}^3 \left({\partial v_i\over\partial x_i}+{\partial
\dot v_i\over\partial v_i}\right)$  
  $\displaystyle =$ $\displaystyle \sum_{i=1}^3 -{\partial\over\partial v_i}\left({\partial\Phi\over
\partial x_i}\right)$  
  $\displaystyle =$ $\displaystyle 0\,.$ (8.17)

Here, $ \partial v_i/\partial x_i=0$ since the positions and velocities of the stars are independent variables, and the second term is zero because the gravitational acceleration $ \partial\Phi/\partial x_i$ does not depend on velocity.

We can use this equation to simplify the continuity equation, and to obtain

$\displaystyle {\partial f\over\partial t}+\sum_{\alpha=1}^6\dot l_\alpha{\partial f\over\partial l_\alpha}=0\,.$ (8.18)

Rewriting in terms of positions and velocities, we obtain the collisionless Boltzmann equation,

$\displaystyle {\partial f\over\partial t} + \sum_{i=1}^3\left(v_i{\partial f\ov...
...l x_i}-{\partial\Phi\over\partial x_i}{\partial f\over\partial v_i}\right)=0\,.$ (8.19)

or in vector notation

$\displaystyle {\partial f\over\partial t}+\hbox{$\bf v$}\cdot{\partial f\over\p...
...l \hbox{$\bf r$}}-\nabla\Phi\cdot {\partial f\over \partial\hbox{$\bf v$}}=0\,.$ (8.20)


next up previous contents
Next: Moments of the Boltzmann Up: Jeans equations Previous: A continuity equation
Tom Theuns
平成19年2月7日